Set, Relation and FunctionHard
Question
Let f:R →
, where f(x) = tan-1
, then-
, where f(x) = tan-1
, then-Options
A.f(x) is continuous everywhere
B.f(x) is into function
C.graph of f(x) is symmetric about the line x = 2
D.f(x) is onto function
Solution
(A) f(x) is continuous everywhere because denominator never become zero.
(B) f(x) = tan-1
f(x) → ∞ not possible & it is an into function.
(C) graph is symmetric about the line x = 2, because of |x - 2|
(B) f(x) = tan-1

f(x) → ∞ not possible & it is an into function.
(C) graph is symmetric about the line x = 2, because of |x - 2|
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
Let S = {1, 2, 3, 4}. The total number of unordered pairs of disjoint subsets of S is equal to...Among 1000 families of a city, 40% read newspaper A, 20% read newspaper B, 10% read newspaper C, 5% read both A and B, 3...For real x, let f (x) = x3 + 5x + 1, then...Let R be the real line. Consider the following subsets of the plane R × R. S = {(x, y) : y = x + 1 and 0...If $\ln(a^b) = e^2$, then find the values of a and b....