Set, Relation and FunctionHard
Question
Let f:R →
, where f(x) = tan-1
, then-
, where f(x) = tan-1
, then-Options
A.f(x) is continuous everywhere
B.f(x) is into function
C.graph of f(x) is symmetric about the line x = 2
D.f(x) is onto function
Solution
(A) f(x) is continuous everywhere because denominator never become zero.
(B) f(x) = tan-1
f(x) → ∞ not possible & it is an into function.
(C) graph is symmetric about the line x = 2, because of |x - 2|
(B) f(x) = tan-1

f(x) → ∞ not possible & it is an into function.
(C) graph is symmetric about the line x = 2, because of |x - 2|
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
Let f(x) = , a > 0, x ≥ 0, then which of the following is/are correct ?...A natural number is selected at random from the set 1 ≤ x ≤ 100. The probability that the number satisfy the...If X and Y are two sets, then equals-...The relation R defined in A = {1, 2, 3} by aRb if |a2 − b2| ≤ 5. Which of the following is false...The relation R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3), (1, 3)} on the set A = {1, 2, 3} is -...