Question

$E = \frac{\frac{\sqrt{3}}{sin20^{\circ}} - \frac{1}{cos20^{\circ}}}{\frac{1}{2} \cdot \frac{1}{4} \cdot cos60^{\circ}}$

$${= \frac{\left( \sqrt{3}cos20^{\circ} - sin20^{\circ} \right)}{cos20^{\circ} \cdot sin20^{\circ}}16 }{= \frac{\left( \frac{\sqrt{3}}{2}cos20^{\circ} - \frac{1}{2}sin20^{\circ} \right)32 \times 2}{2cos20^{\circ} \cdot sin20^{\circ}} }{= \frac{sin40^{\circ}}{sin40^{\circ}} \times 64 = 64}$$