A body falling from rest under gravity passes a certain point P. It was at a distance of 400 m from

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A body falling from rest under gravity passes a certain point P. It was at a distance of 400 m from P, 4s prior to passing through P. If g = 10 m/s2, then the height above the point P from where the body began to fall is

Accepted Answer

We have h = gt2 and h + 400 = g(t + 4)2. Subtracting we get 400 = 8g + 4gt &#8658; t = 8 sec &#8756; h = &#215; 10 &#215; 64 = 320 m &#8756; Desired height = 320 + 400 = 720 m.

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