Trigonometric EquationHard
Question
A body falling from rest under gravity passes a certain point P. It was at a distance of 400 m from P, 4s prior to passing through P. If g = 10 m/s2, then the height above the point P from where the body began to fall is
Options
A.720 m
B.900 m
C.320 m
D.680 m
Solution
We have h =
gt2 and h + 400 = g(t + 4)2.Subtracting we get 400 = 8g + 4gt
⇒ t = 8 sec
∴ h =
× 10 × 64 = 320 m∴ Desired height = 320 + 400 = 720 m.
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