Chemical Kinetics and Nuclear ChemistryMedium
Question
Given above is the concentration vs time plot for a dissociation reaction : $A \rightarrow nB$.
Based on the data of the initial phase of the reaction (initial 10 min ), the value of n is $\_\_\_\_$ .
Options
A.4
B.3
C.2
D.5
Solution
A → nB
$${0.05\ \ \ \ \ \ \ \ \ \ 0 }{0.04\ \ \ \ \ \ \ \ 0.01 \times n }{0.01 \times n = 0.03 }{n = 3}$$
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