Chemical Kinetics and Nuclear ChemistryHard

Question

Given above is the concentration vs time plot for a dissociation reaction : $A \rightarrow nB$.

Based on the data of the initial phase of the reaction (initial 10 min ), the value of n is $\_\_\_\_$ .

Options

A.4
B.3
C.2
D.5

Solution

A → nB

$${0.05\ \ \ \ \ \ \ \ \ \ 0 }{0.04\ \ \ \ \ \ \ \ 0.01 \times n }{0.01 \times n = 0.03 }{n = 3}$$

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