ElectrostaticsHard
Question
Two point charges $2q$ and $q$ are placed at vertex $A$ and centre of face CDEF of the cube as shown in figure. The electric flux passing through the cube is :
Options
A.$\frac{3q}{\varepsilon_{0}}$
B.$\frac{q}{\varepsilon_{0}}$
C.$\frac{3q}{2\varepsilon_{0}}$
D.$\frac{3q}{4\varepsilon_{0}}$
Solution
$\phi = \frac{Q_{\text{in~}}}{\varepsilon_{0}}$
$$\phi = \frac{\frac{q}{4} + \frac{q}{2}}{\varepsilon_{0}} = \frac{3q}{4\varepsilon_{0}}$$
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
Force between two identical spheres charged with same charge is F. If 50% charge of one sphere is transferred to second ...A non - conducting ring of radius 0.5 m carries a total charge 1.11 × 10-10 C distributed non- uniformly on its cir...In an electron gun, electrons are accelerated through a potential difference of V volt. Taking electronic charge and mas...Figure below show regular hexagon, the charges are placed at the vertices. In which of the following cases the electric ...Two small conductors A and B are given charges q1 and q2 respectively. Now they are placed inside a hollow metallic cond...