Electromagnetic WavesMedium
Question
A laser beam has intensity of $4.0 \times 10^{14}\text{ }W/m^{2}$. The amplitude of magnetic field associated with beam is ………. T. ( Take $\epsilon_{0} = 8.85 \times 10^{- 12}C^{2}/{Nm}^{2}$ and $c = 3 \times 10^{8}\text{ }m/s$ )
Options
A.2.0
B.18.3
C.5.5
D.1.83
Solution
$I = \frac{1}{2} \in_{0}E_{0}^{2} \cdot C$
$${\therefore E_{0} = \sqrt{\frac{2I}{\epsilon_{0}C}} }{\&\frac{E_{0}}{{\text{ }B}_{0}} = C }{\therefore B_{0} = \frac{E_{0}}{C} = \frac{1}{C}\sqrt{\frac{2I}{\epsilon_{0}C}} }{\therefore B_{0} = \frac{1}{3 \times 10^{8}}\sqrt{\frac{2 \times 4 \times 10^{14}}{8.85 \times 10^{- 12} \times 3 \times 10^{8}}} }{B_{0} = \frac{10}{3}\sqrt{\frac{8}{8.85 \times 3}} }{B_{0} = 1.83\text{ }T}$$
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