Permanent magnetismEasy
Question
A vibration magnetometer consists of two identcial bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is 25/4 sec. One of the magnets is removed and if the other magnet oscillates in the same field, then the time period in seconds is :-
Options
A.21/4
B.21/2
C.2
D.25/4
Solution
Magnetic moment is a vector quantity. If the magnetic moments of the two magnets are M each then, the net magnetic moment when the magnets are placed perpendicular to each other, is
Meff =
= M√2
and the moment of inertia is 2I.
Thus, T = 2π
when one of the magnets is withdrawn, the time period is
T′ = 2π
∴
or T′ = 
= 2sec
Meff =
= M√2and the moment of inertia is 2I.
Thus, T = 2π
when one of the magnets is withdrawn, the time period is
T′ = 2π
∴
or T′ = = 2secCreate a free account to view solution
View Solution FreeMore Permanent magnetism Questions
The magnetic moment of a short magnet is 8 Am2. The magnetic induction at a point 20cm away from its mid point on (i) ax...Which of the following demonstrated that earth has a magnetic field :-...A magnetic needle is kept in a non-uniform magnetic field. It experiences...The length of a magnet is large compared to its width and breadth.The time period of its oscillation in a vibration magn...A magnet 10 cm long and having a pole strength 2 A-m is deflected through 30o from the magnetic meridian. The horizontal...