Fluid MechanicsHard
Question
A cubical block of wood 10 cm on a side, floats at the interface of oil and water as shown in figure. The density of oil is 0.6 g cm-3 and density of water is 1 g cm-3. The mass of the block is
Options
A.706 g.
B.607 g.
C.760 g.
D.670 g.
Solution
As, weight = Buoyant force
mg = [100 × 6 × 0.6 g] + (100 × 1 × 4)g
∴ m = 760 gm.
mg = [100 × 6 × 0.6 g] + (100 × 1 × 4)g
∴ m = 760 gm.
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