SHMHard

Question

A simple pendulum has a bob with mass $m$ and charge q . The pendulum string has negligible mass. When a uniform and horizontal electric field $\overrightarrow{E}$ is applied, the tension in the string changes. The final tension in the string, when pendulum attains an equilibrium position is $\_\_\_\_$ .

(g : acceleration due to gravity)

Options

A.$mg - qE$
B.$mg + qE$
C.$\sqrt{m^{2}g^{2} + q^{2}E^{2}}$
D.$\sqrt{m^{2}g^{2} - q^{2}E^{2}}$

Solution

$$T = \sqrt{(qE)^{2} + (mg)^{2}}$$

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