SHMHard
Question
A pendulum isA pendulum is suspended in a lift and its period of oscillation when the lift is stationary is T0. What must be the acceleration of the lift so that the period of oscillation of the pendulum to be T0/2 ?
Options
A.2g downward
B.2g upward
C.3g downward
D.3g upward
Solution
T0 = 
.....(i)
Now
..........(ii)
⇒
= 4 ⇒ a = 3g (upwards)
.....(i)Now
..........(ii)⇒
= 4 ⇒ a = 3g (upwards)Create a free account to view solution
View Solution FreeMore SHM Questions
Which of the following quantities are always non-negative in a simple harmonic motion along a straight line?...The maximum velocity of simple harmonic motion represented by y = 3 sinis given by...A string OP of length L is fixed at both ends and vibrates in its first overtone with time period T and maximum amplitud...A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ω0. An exte...Time period of small oscillation (in a vertical plane normal to the plane of strings) of the bob in the arrangement show...