Mole ConceptHard
Question
In the reaction,
$$2Al(s) + 6HCl(aq) \rightarrow 2{Al}^{3 +}(aq) + 6{Cl}^{-}(aq) + 3H_{2}(\text{ }g) $$
Options
A.$11.2\text{ }LH_{2}(\text{ }g)$ at STP is produced for every mole of HCl consumed.
B.$67.2\text{ }LH_{2}(\text{ }g)$ at STP is produced for every mole of Al that reacts.
C.$12\text{ }LHCl(aq)$ is consumed for every $6\text{ }LH_{2}(\text{ }g)$ produced.
D.$33.6\ {\text{ }L}_{2}\ H_{2}(\text{ }g)$ is produced regardless of temperature and pressure for every mole of Al that reacts.
Solution
$2Al(s) + 6HCl(aq) \rightarrow 2{Al}^{3 +}(aq) + 6{Cl}^{-}(aq) + 3H_{2}(\text{ }g)$
Mole of $H_{2}$ produced
$= 2 \times$ mole of HCl used
$= \frac{2}{3} \times$ mole of Al used
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