Mole ConceptHard
Question
In the reaction. 2Al(s) + 6HCl(s) → 2Al3+(aq) + 6Cl-(aq) + 3H2(g),
Options
A.6 L HCl(aq) is consumed for every 3L H2(g) produced
B.33.6 L H2(g) is produced regardless of temperature and pressure for every mole Al that reacts
C.67.2 L H2(g) at STP is produced for every mole Al that reacts
D.11.2 L H2(g) at STP is produced for every mole HCl(aq) consumed
Solution
2Al(s) + 6HCl(aq) → 2Al3+(aq) + 6Cl- (aq) + 3H2(g)
For each mole of HCl reacted, 0.5 mole of H2 gas is formed at STP.1 mole of an ideal gas occupies 22.4 lit at STP.
Volume of H2 gas formed at STP per mole of HCl reacted is 22.4 × 0.5 litre
Hence, (4) is correct.
For each mole of HCl reacted, 0.5 mole of H2 gas is formed at STP.1 mole of an ideal gas occupies 22.4 lit at STP.
Volume of H2 gas formed at STP per mole of HCl reacted is 22.4 × 0.5 litre
Hence, (4) is correct.
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