Atomic StructureHard
Question
Consider the following spectral lines for atomic hydrogen:
A. First line of Paschen series
B. Second line of Balmer series
C. Third line of Paschen series
D. Fourth line of Bracket series
The correct arrangement of the above lines in ascending order of energy is:
Options
A.D $<$ C $<$ A $<$ B
B.A $<$ B $<$ C $<$ D
C.C $<$ D $<$ B $<$ A
D.D $<$ A $<$ C $<$ B
Solution
$\Delta E = 13.6Z^{2}\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)$
| $\ $ Series | $$n_{1}$$ | $$n_{2}$$ |
|---|---|---|
| (A) Paschen $\left( 1^{\text{st~}} \right.\ $ line $)$ | 3 | 4 |
| (B) Balmer $\left( 2^{\text{nd~}} \right.\ $ line $)$ | 2 | 4 |
| (C) Paschen $\left( 3^{\text{rd~}} \right.\ $ line $)$ | 3 | 6 |
| (D) Bracket $\left( 4^{\text{th~}} \right.\ $ line $)$ | 4 | 8 |
So correct ascending order of energy of above lines is : 4
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