Quadratic EquationHard
Question
If the equations $ax^{2} + bx + c = 0$ and $cx^{2} + bx + a = 0,a,b,c \in R$ and $ac \neq 0$ have $a$ common non real root, then
Options
A.$a = - c$
B.$a = c$
C.$|b| > 2|a|$
D.$|b| < 2|a|$
Solution
$D_{1} = b^{2} - 4ac$ and $D_{2} = b^{2} - 4ac$
$$\Rightarrow \ D_{1} < 0\text{~and~}D_{2} < 0$$
⇒ Equation have both roots common
$$\begin{matrix} \Rightarrow & \frac{a}{c} = \frac{b}{b} = \frac{c}{a} \\ \Rightarrow & a = c\text{~and~}b^{2} < 4ac = 4a^{2} \\ & - 2|a| < |b| < 2|a| \end{matrix}$$
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