Quadratic EquationHard
Question
The equation esinx - e-sinx - 4 = 0 has :
Options
A.exactly four real roots.
B.infinite number of real roots.
C.no real roots.
D.exactly one real root.
Solution
Given esinx - e-sinx = 4
let esinx = y
⇒ y2 - 4y - 1 = 0
but we know that
so esinx ≠ 2 + √ 5 and 2 - √5
so No real solution of given equation.
let esinx = y
⇒ y2 - 4y - 1 = 0 but we know that
so esinx ≠ 2 + √ 5 and 2 - √5
so No real solution of given equation.
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