Chemical Kinetics and Nuclear ChemistryHard
Question
Consider the following statements. The law for the acid-catalysed hydrolysis of an ester being given as rate = K [H+] [ester] = K ′ [ester]. If the acid (strong) concentration is doubled at constant ester concentration,
1. the second-order rate constant, K, is doubled.
2. the pseudo first-order rate constant, K ′ is doubled.
3. the rate of reaction is doubled.
Which of the above statement is correct?
Options
A.1 and 2
B.2 and 3
C.1 and 3
D.1, 2 and 3
Solution
K′ = K⋅[H+]
On doubling [H+], K′ will double but K will remain unchanged.
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
The correct increasing order of basic strength for the following compounds is :...$t_{100\%}$ is the time required for the $100\%$ completion of the reaction while $t_{1/2}$ is the time required for $50...the density of gold is 19g/cm3. If 1.9 × 10-4g of gold is dispersed in one litre of water to give a sol having sphe...Milk is colloid in which :...Consider the following consecutive first-order reaction. $A\overset{\quad K_{1}\quad}{\rightarrow}B\overset{\quad K_{2}\...