Chemical Kinetics and Nuclear ChemistryHard

Question

The decomposition of hydrogen peroxide in aqueous solution is a first-order reaction

Time in minutes 0 10

Volume (V, in ml) 25.0 20.0

Here, V is the number of ml of potassium permanganate required to decompose a definite volume of hydrogen peroxide solution at the given time. From the following data, the rate constant (in min−1) of reaction is (ln 5 = 1.6, ln 2 = 0.7)

Options

A.0.09
B.0.02
C.0.2
D.0.16

Solution

$K = \frac{1}{t}.\ln\frac{V_{0}}{V} = \frac{1}{10\text{ min}}.\ln\frac{25}{20} = 0.02\text{ mi}\text{n}^{- 1}$

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