Chemical Kinetics and Nuclear ChemistryMedium
Question
t1/2 of a reaction: A → Products $\left( \text{Order = }\frac{3}{2} \right)$ is represented by $t_{1/2}\alpha\frac{1}{\left\lbrack A_{0} \right\rbrack^{m}}$
The value of m is
Options
A.0.5
B.−0.5
C.1.5
D.−1.5
Solution
$t_{1/2}\alpha\left\lbrack A_{0} \right\rbrack^{1 - n} \Rightarrow 1 - \frac{3}{2} = - m \Rightarrow m = 0.5$
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