Chemical Kinetics and Nuclear ChemistryMedium
Question
The first order rate constant for a certain reaction increase from 1.667 × 10-6 s-1 at 727oC to 1.66 × 10-4s-1 at 1571oC. The rate constant at 1150oC assuming constancy of activation energy over the given temprature range is
[Given : log 19.9 = 1.299][2009]
[Given : log 19.9 = 1.299][2009]
Options
A.3.911 × 10-5s-1
B.1.139 × 10-5s-1
C.3.318 × 10-5s-1
D.1.193 × 10-5s-1
Solution
log 
or 2.030 log
2.030 log
2.030 × 2 =
.......(1)
∴
2.030log
=
......(2)
Dividing equation (2)by equation (1)
∴ log
2 ×
= 1.299
On taking Antilog., k3 = 19.9
∴ k3 = 19.9 × 1.667 × 10-6 = 3.318 × 10-5s-1
or 2.030 log
2.030 log
2.030 × 2 =
.......(1)∴
2.030log
=
......(2)Dividing equation (2)by equation (1)
∴ log
2 ×
= 1.299On taking Antilog., k3 = 19.9
∴ k3 = 19.9 × 1.667 × 10-6 = 3.318 × 10-5s-1
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