Chemical Kinetics and Nuclear ChemistryHard

Question

For the first-order reaction t99% = x × t90%. The value of ‘x’ will be

Options

A.10
B.6
C.3
D.2

Solution

$t_{99\%} = x \times t_{90\%}$

$\Rightarrow \frac{1}{K}.\ln\frac{100}{1} = x.\frac{1}{K}.\ln\frac{100}{10} \Rightarrow x = 2$

Create a free account to view solution

View Solution Free
Topic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions

More Chemical Kinetics and Nuclear Chemistry Questions

The time taken in 75% completion of a zero-order reaction is 10 h. In what time, the reaction will be 90% completed?...t1/2 of a reaction: A → Products $\left( \text{Order = }\frac{3}{2} \right)$ is represented by $t_{1/2}\alpha\frac{1}{\l...95Am241 and 90Th234 belong respectively to :...In most case, for a rise of 10K temperature the rate constant is doubled to tripled. This is due to the reason that...The rate of chemical reactions is independent of...