Chemical Kinetics and Nuclear ChemistryHard

Question

For the first-order reaction t99% = x × t90%. The value of ‘x’ will be

Options

A.10
B.6
C.3
D.2

Solution

$t_{99\%} = x \times t_{90\%}$

$\Rightarrow \frac{1}{K}.\ln\frac{100}{1} = x.\frac{1}{K}.\ln\frac{100}{10} \Rightarrow x = 2$

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