Chemical Kinetics and Nuclear ChemistryHard
Question
For a chemical reaction X → Y, the rate of reaction increases by a factor of 1.837 when the concentration of X is increased by 1.5 times. The order of the reaction with respect to X is
Options
A.1
B.1.5
C.2
D.−1
Solution
$r = K.\lbrack A\rbrack^{n}$
$\therefore\frac{r_{2}}{r_{1}} = \left( \frac{\left\lbrack A_{2} \right\rbrack}{\left\lbrack A_{1} \right\rbrack} \right)^{n} \Rightarrow 1.837 = (1.5)^{n} \Rightarrow n = 1.5$
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