For a chemical reaction X → Y, the rate of reaction increases by a factor of 1.837 when the concentr

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For a chemical reaction X → Y, the rate of reaction increases by a factor of 1.837 when the concentration of X is increased by 1.5 times. The order of the reaction with respect to X is

Accepted Answer

$r = K.\lbrack Abrack^{n}$$	herefore\frac{r_{2}}{r_{1}} = \left( \frac{\left\lbrack A_{2} ightbrack}{\left\lbrack A_{1} ightbrack} ight)^{n} \Rightarrow 1.837 = (1.5)^{n} \Rightarrow n = 1.5$

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