ThermodynamicsHard
Question
For the cyclic process given below, which of the following relations are correct?
Options
A.$\Delta S = S_{2} - S_{1} = \int_{1}^{2}\frac{\delta q_{rev}}{T}$
B.$\Delta S = S_{1} - S_{2} = \int_{2}^{1}\frac{\delta q_{irr}}{T}$
C.$\Delta S_{\text{cycle}} = 0 = \int_{1}^{2}{\frac{\delta q_{rev}}{T} +}\int_{2}^{1}\frac{\delta q_{irr}}{T}$
D.$\Delta S_{\text{cycle}} = 0 > \left( \int_{1}^{2}{\frac{\delta q_{rev}}{T} +}\int_{2}^{1}\frac{\delta q_{irr}}{T} \right)$
Solution
$dS = \frac{r_{rev}}{T}\text{ and }\oint_{}^{}{dS} = 0$
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