A reversible heat engine absorbs 40 kJ of heat at 500 K and performs 10 kJ of work rejecting the rem

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A reversible heat engine absorbs 40 kJ of heat at 500 K and performs 10 kJ of work rejecting the remaining amount to the sink at 300 K. The entropy change for the universe is

Accepted Answer

$\Delta S_{unit} = \Delta S_{source} + \Delta S_{Heatengine} + \Delta S_{	ext{sink}}$$= - \frac{40 	imes 10^{3}}{500} + 0 + \frac{30 	imes 10^{3}}{300} = + 20	ext{ J/K}$

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