ThermodynamicsHard
Question
Consider a reversible isentropic expansion of 1 mole of an ideal monoatomic gas from 27°C to 927°C. If the initial pressure of gas was 1 bar, then the final pressure of gas becomes
Options
A.4 bar
B.8 bar
C.32 bar
D.0.25 bar
Solution
$\Delta S = n.C_{P,m}.\ln\frac{T_{2}}{T_{1}} + nR.\ln\frac{P_{1}}{P_{2}}$
$\text{Or, }0 = n \times \frac{5}{2}R \times \ln\frac{1200}{300} + nR \times \ln\frac{1}{P_{2}} \Rightarrow P_{2} = 32\text{ bar}$
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