ThermodynamicsHard
Question
If the enthalpy change for the transition of liquid water to steam is 30 kJ mol-1 at 27oC, the entropy change for the process would be
Options
A.1.0 J mol-1 K-1
B.1.0 J mol-1 K-1
C.100 J mol-1 K-1
D.10 J mol-1 K-1
Solution
ᐃGo = ᐃHo - TᐃSo
Given, ᐃHvap = 30 kJ mol-1
ᐃGo = 0 at equilibrium,
= 100 J mol-1 K-1
Given, ᐃHvap = 30 kJ mol-1
ᐃGo = 0 at equilibrium,
= 100 J mol-1 K-1
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