A real gas is subjected to an adiabatic process from (2 bar, 40 L, 300 K) to (4 bar, 30 L, 300 K) ag

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A real gas is subjected to an adiabatic process from (2 bar, 40 L, 300 K) to (4 bar, 30 L, 300 K) against a constant pressure of 4 bar. The enthalpy change for the process is

Accepted Answer

$q = 0 \Rightarrow \Delta U = w = - P_{ext}.\left( V_{2} - V_{1} \right) = - 4 \times (30 - 40) = 40l - \text{bar}$

Now, $\Delta H = \Delta U + \Delta(PV) = 40 + (4 \times 30 - 2 \times 40) = 80\text{L-atm = 8000 J}$

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