ThermodynamicsMedium
Question
The value of log10K for a reaction A ⇋ B is
( Given : áƒfHo298K = - 54.07 kJ mol-1, áƒrSo298K = 10JK-1mol-1 and R = 8.314 JK-1mol-1 ; 2.303 × 8.314 × 298 = 5705)
Options
A.5
B.10
C.95
D.100
Solution
áƒGo = áƒHo - TáƒSo = - 54.07 × 1000 - 298 × 10 = - 57050 J mol-1 - 57050 = - 5705 log10K
log10K = 10
Hence (B) is correct
log10K = 10
Hence (B) is correct
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