If one mole of a monoatomic gas ($\gamma$ = 5/3) is mixed with one mole of a diatomic gas ($\gamma$

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If one mole of a monoatomic gas ($\gamma$ = 5/3) is mixed with one mole of a diatomic gas ($\gamma$ = 7/5), then the value of $\gamma$ for the mixture is

Accepted Answer

$\gamma_{mix} = 1 + \frac{\left( n_{1} + n_{2} ight).R}{n_{1}.C_{v,m,1} + n_{2}.C_{v,m,2}} = 1 + \frac{(1 + 1) 	imes R}{1 	imes \frac{R}{\frac{5}{3} - 1} + 1 	imes \frac{R}{\frac{7}{5} - 1}} = 1.5$

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