ThermodynamicsMedium
Question
If one mole of a monoatomic gas ($\gamma$ = 5/3) is mixed with one mole of a diatomic gas ($\gamma$ = 7/5), then the value of $\gamma$ for the mixture is
Options
A.1
B.1.5
C.2
D.3.0
Solution
$\gamma_{mix} = 1 + \frac{\left( n_{1} + n_{2} \right).R}{n_{1}.C_{v,m,1} + n_{2}.C_{v,m,2}} = 1 + \frac{(1 + 1) \times R}{1 \times \frac{R}{\frac{5}{3} - 1} + 1 \times \frac{R}{\frac{7}{5} - 1}} = 1.5$
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