The minimum work which must be done to compress 16 g of oxygen isothermally at 300 K from a pressure

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The minimum work which must be done to compress 16 g of oxygen isothermally at 300 K from a pressure of 1.01325 × 103 N/m2 to 1.01325 × 105 N/m2 is (ln100 = 4.6, R = 8.3 J/K-mol)

Accepted Answer

For minimum work in compression, the process must be reversible.

$w = - nRT.\ln\frac{P_{1}}{P_{2}} = - \frac{16}{32} \times 8.3 \times 300 \times \ln\frac{1.01325 \times 10^{3}}{1.01325 \times 10^{25}} = + 5727\text{ J}$

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