The specific conductance of AgCl solution in water was determined to be 1.8 × 10−6 Ω−1 cm−1 at 298 K

Question

The specific conductance of AgCl solution in water was determined to be 1.8 × 10−6 Ω−1 cm−1 at 298 K. The molar conductances at infinite dilution, of Ag+ and Cl− are 67.9 and 82.1 Ω−1 cm2 mol−1, respectively. What is the solubility of AgCl in water?

Accepted Answer

For AgCl, $\Lambda_{m}^{o} = \Lambda_{m} = \lambda_{m\left( Ag^{+} \right)}^{o} + \lambda_{m\left( Cl^{-} \right)}^{o}$

= 67.9 + 82.1 = 150 ohm^–1 cm² mol^–1

Now, $\Lambda_{m} = \frac{k}{C} \Rightarrow 150 = \frac{1.8 \times 10^{- 6}}{s}$

$\therefore S = 1.2 \times 10^{- 8}\text{ mol c}\text{m}^{- 3} = 1.2 \times 10^{- 5}\text{ mol }\text{e}^{- 1}$

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