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Question

Sodium amalgam is prepared by electrolysis of aqueous NaCl using 10 g mercury as cathode. How many Faraday of electricity is required to prepare 18.7% Na-amalgam, by weight, with a current efficiency of 50%? (a) 0.1 F (b) 0.2 F (c) 0.05 F (d) 0.16 F

Options

A.0.1 F
B.0.2 F
C.0.05 F
D.0.16 F

Solution

Mass of Na deposited $= \frac{18.7}{(100 - 18.7)} \times 10 = 2.623\text{ gm}$

Now, $n_{eq} = \frac{Q}{F} \Rightarrow \frac{2.623}{23} \times 1 = \frac{Q}{F} \times 0.5 \Rightarrow Q \approx 0.2\text{ F}$

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