ElectrochemistryHard

Question

A certain current liberated 0.50 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution? (Cu = 63.5)

Options

A.12.7 g
B.15.88 g
C.31.75 g
D.63.5 g

Solution

$n_{eq}H_{2} = n_{eq}Cu \Rightarrow \frac{0.5}{1} = \frac{w}{63.5} \times 2$

$\Rightarrow w = 15.875\text{ gm}$

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