ElectrochemistryMedium
Question
The standard reduction potentials in acidic conditions are 0.77 V and 0.53 V, respectively, for Fe3+|Fe2+ and I3−|I− couples. The equilibrium constant for the reaction: 2Fe3+ + 3I− $\rightleftharpoons$2Fe2+ + I3−, is (2.303 RT/F = 0.06)
Options
A.2 × 108
B.108
C.104
D.10−8
Solution
$E_{cell}^{o} = \frac{0.06}{n}.\log K_{eq}$
$\Rightarrow (0.77 - 0.53) = \frac{0.06}{2}.\log K_{eq} $$$\therefore K_{eq} = 10^{8}$$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The standard electrode potential ( $E^{\circ}$ ) for the half-cell reaction ${Fe}^{3 +} + e^{-} \rightarrow {Fe}^{2 +}$ ...In salt bridge, normally KCl is used because...Choose the correct statement(s)....For a cell reaction involving two electron change, the standard EMF of the cell is 0.295 V at 2oC. The equilibrium const...The equivalent conductivity of KCl at infinite dilution is 130 S cm2 eq-1. The transport number of Cl-1 ion in KCl at th...