ThermochemistryHard
Question
In certain areas where coal is cheap, artificial gas is produced for house hold use by the ‘water gas’ reaction.
C(s) + H2O(g) → H2(g) + CO(g)
Assume that coke is 100% carbon.
Given ΔHC (kcal/mol) at 25o C: H2(g) = −68.0; CO(g) = −68.0; C(s) = −94.0.
Options
A.The maximum heat obtainable at 25o C from the combustion of 1.2 kg of coke is 9400 kcal.
B.The maximum heat obtainable at 25o C from burning water gas produced from 1.2 kg of coke is 13,600 kcal.
C.The maximum heat obtainable at 25o C from burning 1.2 kg of water gas is 5440 kcal.
D.The maximum heat obtainable at 25o C from burning water gas or burning the same mass of coke will be same.
Solution
$(a)n_{C(s)} = \frac{1.2 \times 1000}{12} = 100$
∴ Maximum obtainable heat = 100 × 94 = 9400 cal
(b) Heat released = $100 \times 68 + 100 \times 68 = 13600\text{ cal}$
(c) Heat released = $\frac{13600}{100} \times \left( \frac{1200}{30} \right) = 5440\text{ cal}$
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