ThermochemistryHard

Question

Enthalpy of neutralisation of CH3COOH by NaOH is - 50.6 kJ/mol and the heat of neutralisation of a strong acid with NaOH is - 55.9 kJ/mol. The value of ᐃH for the ionsation of CH3COOH is :

Options

A.3.5 kJ/mol
B.4.6kJ/mol
C.5.3 kJ/mol
D.6.4 kJ/ mol

Solution

Enthalpy of netutralisation of CH3COOH by NaOH is - 50.6 kJ /mole for strong acid and base this value is 55.9 kJ/mole. Heat evolved in the first case is less as some heat is used up in ionisation of CH3COOH. So, ᐃH for ionosation of CH3COOH = 55.9 - 50.6 = 5.3 kJ/mole

Create a free account to view solution

View Solution Free
Topic: Thermochemistry·Practice all Thermochemistry questions

More Thermochemistry Questions

The heat of neutralization of a strong base and a strong acid is 57 kJ. The heat released when 0.5 mole of HNO3 solution...Which of the following property is correct for the compound having maximum covalent character among the following series...The above p-v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amoun...ᐃHfo(298K) of methanol is given by the chemical equation :...Given that :-CH4(g) + 300 kJ → C(g) + 4H(g)C2H6(g) + 620 kJ → 2C(g) + 6H(g)The value of C - C bond energy is...