ThermochemistryMedium

Question

Enthalpy of neutralisation of CH3COOH by NaOH is - 50.6 kJ/mol and the heat of neutralisation of a strong acid with NaOH is - 55.9 kJ/mol. The value of ᐃH for the ionsation of CH3COOH is :

Options

A.3.5 kJ/mol
B.4.6kJ/mol
C.5.3 kJ/mol
D.6.4 kJ/ mol

Solution

Enthalpy of netutralisation of CH3COOH by NaOH is - 50.6 kJ /mole for strong acid and base this value is 55.9 kJ/mole. Heat evolved in the first case is less as some heat is used up in ionisation of CH3COOH. So, ᐃH for ionosation of CH3COOH = 55.9 - 50.6 = 5.3 kJ/mole

Create a free account to view solution

View Solution Free
Topic: Thermochemistry·Practice all Thermochemistry questions

More Thermochemistry Questions

The Δf Ho for CO2(g), CO(g) and H2O(g) are −393.5, −110.5 and −241.8 kJ mol–1, respectively. The standard enthalpy chang...If x1, x2 and x3 are enthalpies of H - H, O = O and O - H bonds respectively, and x4 is the enthalpy of vaporisation of ...The molar heat capacities at constant pressure (assumed constant with respect to temperature) at A,B and C are in ratio ...What is the enthalpy change for the isomerization reaction?CH2=CH–CH2–CH=CH–CH=CH2 (A) $\overset{\quad NaNH_{2}\Delta\qu...Calculate the enthalpy of formation (in kcal/mol) of HI(g) from the following data.H2(g) + Cl2(g) → 2HCl(g): ΔH = −44.20...