SolutionHard

Question

PtCl4.6H2O can exist as a hydrated complex. 1.0 molal aqueous solution has depression in freezing point of 3.72°C. Assume 100% ionization and Kf of water = 1.86°C mol−1 kg. The complex is

Options

A.[Pt(H2O)6]Cl4
B.[Pt(H2O)4Cl2]Cl2·2H2O
C.[Pt(H2O)3Cl3]Cl·3H2O
D.[Pt(H2O)2Cl4]·4H2O

Solution

$\Delta T_{f} = K_{f}.m \Rightarrow 3.72 = 1.86 \times 1.0 \times n \Rightarrow n = 2$

∴ From each particle, two ions should form.

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