SolutionHard
Question
A solution of a non-volatile solute in water freezes at −1.0°C. The vapour pressure of pure water at 298 K is 24.24 mm Hg and Kf for water is 1.80 K-kg mol−1. The vapour pressure of this solution at 298 K is
Options
A.24.00 mm Hg
B.22.04 mm Hg
C.24.12 mm Hg
D.23.76 mm Hg
Solution
$\Delta T_{f} = K_{f}.m \Rightarrow 1.0 = 1.80 \times m \Rightarrow m = \frac{1}{1.8}$
$P = X_{2}.P^{o} = \frac{1000/18}{\frac{1}{1.8} + \frac{1000}{18}} \times 24.24 = 24\text{ mm Hg}$
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