SolutionHard
Question
A quantity of 10 g of solute ‘A’ and 20 g of solute ‘B’ is dissolved in 500 ml water. The solution is isotonic with the solution obtained by dissolving 6.67 g of ‘A’ and 30 g of ‘B’ in 500 ml water at the same temperature. The ratio of molar masses, MA: MB, is
Options
A.1: 1
B.3: 1
C.1: 3
D.2: 3
Solution
$C_{1} = C_{2} \Rightarrow \frac{10}{M_{A}} + \frac{20}{M_{B}} = \frac{6.67}{M_{A}} + \frac{30}{M_{B}} \Rightarrow \frac{M_{A}}{M_{B}} = \frac{1}{3}$
Create a free account to view solution
View Solution FreeMore Solution Questions
Consider 0.1 m aqueous solutions of two solutes X and Y. The solute X behaves as a univalent electrolyte, while the solu...A complex containing K+, Pt(IV) and Cl- is 100% ionised giving i = 3. Thus, complex is :...Among the colligative properties of solution, which one is the best method for the determination of molecular masses of ...A semipermeable membrane separates a solution which is 0.012 M in glucose from one that is 0.250 M in glucose. On which ...A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct r...