SolutionHard
Question
A quantity of 10 g of solute ‘A’ and 20 g of solute ‘B’ is dissolved in 500 ml water. The solution is isotonic with the solution obtained by dissolving 6.67 g of ‘A’ and 30 g of ‘B’ in 500 ml water at the same temperature. The ratio of molar masses, MA: MB, is
Options
A.1: 1
B.3: 1
C.1: 3
D.2: 3
Solution
$C_{1} = C_{2} \Rightarrow \frac{10}{M_{A}} + \frac{20}{M_{B}} = \frac{6.67}{M_{A}} + \frac{30}{M_{B}} \Rightarrow \frac{M_{A}}{M_{B}} = \frac{1}{3}$
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