SolutionHard
Question
A liquid mixture of ‘A’ and ‘B’ (assume ideal solution) is placed in a cylinder and piston arrangement. The piston is slowly pulled out isothermally so that the volume of liquid decreases and that of the vapour increases. At the instant when the quantity of the liquid still remaining is negligibly small, the mole fraction of ‘A’ in the vapour is 0.4. If $P_{A}^{o}$= 0.4 atm and $P_{B}^{o}$= 1.2 atm at this temperature, then the total pressure at which the liquid has almost evaporated is
Options
A.0.667 atm
B.1.5 atm
C.0.8 atm
D.0.545 atm
Solution
$\frac{1}{P_{\text{total}}} = \frac{Y_{A}}{P_{A}^{o}} + \frac{Y_{B}}{P_{B}^{o}} = \frac{0.4}{0.4} + \frac{0.6}{1.2} = \frac{3}{2} \Rightarrow \frac{1}{P_{\text{total}}} = \frac{2}{3}\text{ atm}$
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