SolutionHard

Question

A solution containing 2.60 g of a non-volatile and non-electrolyte solute in 200 g of water boils at 100.130°C at 1 atm. What is the molar mass of the solute? [Kb (H2O) = 0.52 K-kg/mol]

Options

A.52.0 g mol−1
B.152.0 g mol−1
C.104 g mol−1
D.204 g mol−1

Solution

$\Delta T_{b} = K_{b}.m \Rightarrow 0.13 = 0.52 \times \frac{2.6/M}{200/1000} \Rightarrow M = 52$

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