SolutionMedium
Question
How many grams of glucose (C6H12O6) should be dissolved in 0.5 kg of water at 25°C to reduce the vapour pressure of the water by 1.0%?
Options
A.50.5 g
B.50.0 g
C.18.0 g
D.18.2 g
Solution
$\frac{P^{o} - P}{P} = \frac{n_{1}}{n_{2}} \Rightarrow \frac{1}{99} = \frac{w/180}{500/18} \Rightarrow w = 50.5\text{ gm}$
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