At 323 K, the vapour pressure (in mm Hg) of a methanol−ethanol solution is represented as P = 120X +

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At 323 K, the vapour pressure (in mm Hg) of a methanol−ethanol solution is represented as P = 120X + 140, where X is the mole fraction of methanol in liquid solution at equilibrium. The value of PoEtOH is

Accepted Answer

When $X = 0 \Rightarrow P = P_{EtOH}^{o} = 140	ext{ mm Hg}$

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