SolutionHard
Question
At 323 K, the vapour pressure (in mm Hg) of a methanol−ethanol solution is represented as P = 120X + 140, where X is the mole fraction of methanol in liquid solution at equilibrium. The value of PoEtOH is
Options
A.120 mm
B.140 mm
C.260 mm
D.20 mm
Solution
When $X = 0 \Rightarrow P = P_{EtOH}^{o} = 140\text{ mm Hg}$
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