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Question
Henry’s law constant for CO2 in water is 1.6 × 108 Pa at 298 K. The quantity of CO2 in 500 g of soda water when packed under 3.2 bar pressure at 298 K is
Options
A.2.44 g
B.24.4 g
C.0.244 g
D.0.61 g
Solution
$P = K_{H}.X \Rightarrow 3.2 \times 10^{5} = 1.6 \times 10^{8} \times \frac{n_{CO_{2}}}{n_{CO_{2}} + \frac{500}{18}}$
$\therefore n_{CO_{2}} \approx 5.5 \times 10^{- 2} \Rightarrow n_{CO_{2}} \approx 2.44\text{ gm}$
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