SolutionMedium
Question
The mass of a non-volatile solute (molecular mass = 40) which should be dissolved in 114 g octane to reduce its vapour pressure to 80% is
Options
A.8 g
B.12 g
C.4 g
D.10 g
Solution
$\frac{P^{o} - P}{P} = \frac{n_{1}}{n_{2}} \Rightarrow \frac{20}{80} = \frac{w/40}{114/114} \Rightarrow w = 10\text{ gm}$
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