Solid StateHard
Question
The correct information regarding a solid element (atomic radius = r) having ABCABC…. type packing (FCC unit cell edge length = a) is
Options
A.the distance between nearest octahedral and tetrahedral void is $\frac{\sqrt{3}a}{4}$.
B.the distance between two nearest octahedral void is $\frac{a}{\sqrt{2}}$.
C.the distance between two nearest tetrahedral void is $\frac{\sqrt{3}a}{2}$.
D.the distance between successive A and B layers is $2r.\sqrt{\frac{2}{3}}$.
Solution
Shortest distance between two T.V. is (a/2).
Create a free account to view solution
View Solution FreeMore Solid State Questions
An element crystallises in a ′bcc′ lattice. Nearest neighbours and next nearest neighbours of the elements a...Platinum crystallises in a face centered cube crystal with a unit cell length of 3.9231 A0. The density and atomic radiu...The unit cell of a metallic element of atomic mass 108 and density 10.5 g/cm3 is a cube with edge length of 409 pm. The ...BaO has a rock-salt type structure. When subjected to high pressure, the ratio of the coordination number of Ba+2 ion to...AB crystallizes in a body centered cubic lattice with edge length ′a′ equal to 387 pm. The distance between ...