Solid StateHard

Question

NaCl is doped with 2 × 10–3 mole% SrCl2, the concentration of cation vacancies is (NA = 6 × 1023)

Options

A.6.0 × 1018 mol−1
B.1.20 × 1019 mol−1
C.3.0 × 1018 mol−1
D.1.20 × 1021 mol−1

Solution

One Sr2+ ion will result removal of two Na+ ion from crystal for neutrality of crystal. One position of Na+ ion will be occupied by Sr2+, but other position will remain vacant.

Number of cation vacancies = Number of Sr2+ ions

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