Ionic EquilibriumHard

Question

At 25o C, the dissociation constants of acid HA and base BOH in aqueous solution is same. The pH of 0.01 M solution of HA is 5.0. The pH of 0.1 M solution of BOH is

Options

A.5.0
B.9.0
C.9.5
D.8.5

Solution

$10^{- 5} = \sqrt{K_{a} \times 0.01} \Rightarrow K_{a} = 10^{- 8}$

Now, $\left\lbrack OH^{-} \right\rbrack = \sqrt{10^{- 8} \times 0.1} = 10^{- 4.5} \Rightarrow P^{OH} = 4.5$

∴ PH = 9.5

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