Ionic EquilibriumHard

Question

The solubility products of Mg(OH)2, Cd(OH)2, Al(OH)3 and Zn(OH)2 are 4 × 10–11, 8 × 10–6, 8.5 × 10–23 and 1.8 × 10–14, respectively. The cation that will precipitate first as hydroxide, on adding limited quantity of NH4OH in a solution containing equimolar amount of metal cations, is

Options

A.Al3+
B.Zn2+
C.Mg2+
D.Cd2+

Solution

[OH ]min to start ppt. of Mg(OH)2 = $\sqrt{\frac{K_{sp}}{\left\lbrack Mg^{2 +} \right\rbrack}} = \sqrt{\frac{4 \times 10^{- 11}}{x}}$

For Cd(OH)2, [OH ]min = $\sqrt{\frac{8 \times 10^{- 6}}{x}}$

For Al(OH)3, [OH ]min = $\left( \frac{8.5 \times 10^{- 23}}{x} \right)^{1/3}$

For Zn(OH)2, [OH ]min = $\sqrt{\left( \frac{1.8 \times 10^{- 14}}{x} \right)}$

Considering significant concentration of metal ion (x is not extremely small), [OH] needed is minimum for Al3+ and hence, it will precipitate first.

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