Ionic EquilibriumHard

Question

What is the solubility product of Al(OH)3 in water?

Given: Al(OH)4– (aq) ­$\rightleftharpoons$Al3+ (aq) + 4OH– (aq); K = 1.3 × 10–34

Al(OH)3(s) + OH– (aq)­$\rightleftharpoons$Al (OH)4– (aq); K = 38.5

Options

A.3.1 × 10−35
B.5 × 10−33
C.6.1 × 10−33
D.5 × 10−34

Solution

Adding both reactions, Ksp = 1.3 × 10–34 × 38.5 ≈ 5 × 10–33

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