Chemical EquilibriumHard
Question
Solid NH4HS dissociates into NH3 and H2S at a certain temperature, the equilibrium pressure is P atm. If now, NH3 is pumped into the system so that its partial pressure becomes P atm, then what will be the partial pressure (in atm) of H2S?
Options
A.0.5 P
B.0.25 P
C.0.33 P
D.0.67 P
Solution
NH4HS(s) $\rightleftharpoons$ NH3 (g) + H2S(g)
Equ. partial pressure $\frac{P}{2}$atm $\frac{P}{2}$atm
New Equ. partial pressure P atm P′ atm
Now, $\frac{P}{2} \times \frac{P}{2} = P \times P' \Rightarrow P' = 0.25\text{ P}$
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